Question

The ratio of mass of 1 mole of sodium and 1 atom of sodium is:

• A. $6.02\times {10}^{23}$
• B. $23$
• C. $\frac{23}{6.02}$
• D. $23\times 6.02$

Answer 1

The correct option is A $6.02\times {10}^{23}$

The mass of $1$ mole of sodium $=23gm$

because molecular mass of sodium is $23gm/mole$.

So, $6.023\times {10}^{23}$ atoms have total mass $23gm$

$\therefore$ The mass of $1$ sodium atom $=\frac{23}{6.023\times {10}^{23}}$

The ratio of mass of $1$ mole of sodium and $1$ atom of sodium $=23÷\frac{23}{6.023\times {10}^{23}}=6.023\times {10}^{23}$