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Standard XII

Chemistry

Molarity

The ratio of ...

Question

The ratio of mass of hydrogen and magnesium deposited by the same amount of electricity from
H $_{2}$ SO $_{4}$ and MgSO $_{4}$ is :

1:8

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1:12

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1:16

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1:32

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Solution

The correct option is A 1:12
Equivalent weight of hydrogen = 1
Equivalent weight of magnesium =12
Substitute values in the following equation
$\frac{M a s s o f H_{2} d e p o s i t e d}{M a s s o f M g d e p o s i t e d} = \frac{E q . W t o f H_{2}}{E q . W t o f M g} = \frac{1}{12} .$

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Similar questions

Q. The ratio of weight of hydrogen and magnesium deposited by the same amount of electricity from

H_{2} {S O}_{4}

and

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and fused

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Q. The ratio of weights of hydrogen and magnesium deposited by the same amount of electricity from aqueous

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$M g + H_{2} S O_{4}$ $\to$ $M g S O_{4}$ + $H_{2}$

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and

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are neutralized separately by the same amount of an alkali when sulphate and dihydrogen phosphates are formed respectively.Find the ratio of the masses of

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The ratio of mass of hydrogen and magnesium deposited by the same amount of electricity from H2SO4 and MgSO4 is :

The correct option is A 1:12Equivalent weight of hydrogen = 1Equivalent weight of magnesium =12Substitute values in the following equationMassofH2depositedMassofMgdeposited=Eq.WtofH2Eq.WtofMg=112.

The ratio of mass of hydrogen and magnesium deposited by the same amount of electricity from
H $_{2}$ SO $_{4}$ and MgSO $_{4}$ is :

The correct option is A 1:12
Equivalent weight of hydrogen = 1
Equivalent weight of magnesium =12
Substitute values in the following equation
$\frac{M a s s o f H_{2} d e p o s i t e d}{M a s s o f M g d e p o s i t e d} = \frac{E q . W t o f H_{2}}{E q . W t o f M g} = \frac{1}{12} .$