The ratio of number of molecules in equal weights of $H_{2}$ , He and $C H_{4}$ is

1 : 1 : 1

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1 : 2 : 3

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8 : 4 : 1

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1 : 2 : 8

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Solution

The correct option is C
8 : 4 : 1

$H_{2} : H e : C H_{4}$

$\frac{1}{2} : \frac{1}{4} : \frac{1}{16}$

$8 : 4 : 1$

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