The ratio of oxygen atom having −2 and −1 oxidation numbers in S2O2−8 is three. If true enter 1, else enter 0.
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Solution
The correct option is A 1 The ratio of oxygen atom having −2 and −1 oxidation numbers in S2O2−8 is three as only one peroxy linkage is present. So, we can see from the structure below that the number of oxygen atoms having −2 oxidation state is 6 while those having −1 oxidation state is 2. Hence, the ratio is 62=3.