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Question

The ratio of oxygen atom having 2 and 1 oxidation numbers in S2O28 is three.
If true enter 1, else enter 0.
  1. 1

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Solution

The correct option is A 1
The ratio of oxygen atom having 2 and 1 oxidation numbers in S2O28 is three as only one peroxy linkage is present.
So, we can see from the structure below that the number of oxygen atoms having 2 oxidation state is 6 while those having 1 oxidation state is 2. Hence, the ratio is 62=3.
282946_182248_ans.png

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