The ratio of petrol and kerosine in the container is 3 : 2 when 10 litres of the mixture is taken out and is replaced by the kerosine, the ratio becomes 2 : 3. Initially, the total quantity of the mixture in the container is

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Solution

The correct option is B 30
Suppose the initial ratio of Petrol and Kerosine is 3x and 2x
Quantity of Petrol in mixture left $= (3 x - \frac{3}{5} \times 10) = (3 x - 6)$
Quantity of Kerosine in Mixture left $= (2 x - \frac{2}{5} \times 10) (2 x - 4)$
$\Rightarrow \frac{3 x - 6}{2 x - 4 + 10} = \frac{2}{3}$
$\Rightarrow 9 x - 18 = 4 x + 12$
$\Rightarrow x = 6$
Than total quality of mixture $= 3 x + 2 x = 18 + 12 = 30$

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The ratio of petrol and kerosine in the container is 3 : 2 when 10 litres of the mixture is taken out and is replaced by the kerosine, the ratio becomes 2 : 3. Initially, the total quantity of the mixture in the container is

The correct option is B 30Suppose the initial ratio of Petrol and Kerosine is 3x and 2xQuantity of Petrol in mixture left =(3x−35×10)=(3x−6)Quantity of Kerosine in Mixture left =(2x−25×10)(2x−4)⇒3x−62x−4+10=23⇒9x−18=4x+12⇒x=6Than total quality of mixture =3x+2x=18+12=30