Question

The ratio of pi to sigma bonds in benzene is:

• A. 1 : 4
• B. 1 : 2
• C. 3 : 1
• D. 1 : 6

Answer 1

Answer: (A)

1 : 4

no of $\pi$ Bonds (c-c)=3
no of $\sigma$ Bonds (c-c)=6
no of $\sigma$ bonds (c-h)=6
total $\sigma$ bonds=6+6=12
ratio of $\pi$ and $\sigma =\frac{3}{12}=1:4$