Question

The ratio of radii of nuclei ${}_{13}A{l}^{27}$ and ${}_{52}T{e}^{125}$ is:

• A. $\sqrt{13}:\sqrt{52}$
• B. $\sqrt[3]{313}:\sqrt[3]{352}$
• C. $\sqrt[3]{33}:\sqrt[3]{35}$
• D. $3:5$

Answer 1

Answer: (D)

$3:5$

We know $R\propto A^{1/3}$

$\frac{R_{Al}}{R_{Te}}=\frac{(27{)}^{1/3}}{(125{)}^{1/3}}$$=\frac{3}{5}$