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Nuclear Radius

The ratio of ...

Question

The ratio of radii of nuclei $_{13}^{27}$ Al and $_{52}^{125}$ Te is approximately

A

6 : 10

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B

13 : 52

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C

40 : 177

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D

14 : 7

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Solution

The correct option is A 6 : 10
By using $r \propto A^{\frac{1}{3}} \Rightarrow \frac{r_{1}}{r_{2}} = {(\frac{A_{1}}{A_{2}})}^{\frac{1}{3}} = {(\frac{27}{125})}^{\frac{1}{3}} = \frac{3}{5} = \frac{6}{10}$

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