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Graham's Law of Effusion

The ratio of ...

Question

The ratio of rates of effusion of $S O_{2}$ to $S O_{3}$ is:

\sqrt{\frac{5}{4}}

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\sqrt{\frac{4}{5}}

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\sqrt{\frac{3}{4}}

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\sqrt{\frac{4}{3}}

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Solution

The correct option is A $\sqrt{\frac{5}{4}}$
From Graham's law of effusion,
$\frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$
$\Rightarrow \frac{r_{1}}{r_{2}} = \sqrt{\frac{80}{64}} = \sqrt{\frac{5}{4}}$

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Similar questions

S O_{2}

S O_{3}

S O_{2}

C H_{4}

\frac{n_{S O_{2}}}{n_{C H_{4}}} = \frac{8}{1}

The rates of diffusion of $S O_{2}, C O_{2}, P C l_{3} a n d S O_{3}$ are in the following order –

S O_{2}

C H_{4}

S O_{2}

C H_{4}

(n_{S O_{2}} / n_{C H_{4}} = 8 / 1)

S O_{2}

C H_{4}

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