Question

The ratio of the amounts of energy release as a result of the fussion of 1 kg hydrogen $\left(E_1\right)$ and fission of 1 kg of ${92}^{U^{235}}$ will be

• A. 1.28
• B. 3.28
• C. 5.28
• D. 7.65

Answer 1

The correct option is D 7.65

$$\begin{array}{c}Accordingtoqueation.........\\ Energyrealeasedbyfusionof1kgofhydrogen,\\ =\frac{6\times {10}^{23}\times 26}{4}\times {10}^{3}MeV\\ E_1=39\times {10}^{26}MeV\\ and,\\ Asenergyreleasedinfusionofoneatomof{}_{92}{U}^{235}=200MeV\\ \therefore Energyreleasedinfusionof1kgof{}_{92}{U}^{235}\\ =\frac{6\times {10}^{23}\times 1000}{235}\times 200MeV\\ E_2=5.1\times {10}^{26}MeV\\ thus,\\ \frac{E_1}{E_2}=\frac{39\times {10}^{26}}{5.1\times {10}^{26}}=7.65\\ sotheoptionisD.\end{array}$$