Question

The ratio of the base and the height of a triangle are $4:3$. If the area of the triangle is $216{\text{m}}^2$, find the length and height.

Answer 1

Let Base $=4k$, Height $=3k$; Area $=\frac{1}{2}\times$ base $\times$ height

$\Rightarrow 216=\frac{1}{2}\times 4k\times 3k$

$\Rightarrow 6k^2=216$

$\Rightarrow k^2=36$

$\Rightarrow k=6$

$\Rightarrow$ Base $=24$m,

Height $=18$m.