Question

The ratio of the energies of two different radiations whose frequencies are $3\times {10}^{14}Hz$ and $5\times {10}^{14}Hz$ is:

• A. 3 : 5
• B. 5 : 3
• C. 3 : 1
• D. 5 : 1

Answer 1

The correct option is A 3 : 5

$Energy\propto frequency[E=hv]$

$Ratio=\frac{E_1}{E_2}=\frac{v_1}{v_2}=\frac{3\times {10}^{14}}{5\times {10}^{14}}=\frac{3}{5}$

So, A is the correct option.