Question

The ratio of the heights from which two bodies are dropped is 3:5 respectively then the ratio of the final velocity would be what?

Answer 1

For first body
Since it is freely falling,
u =0
a=g
s=3x ,Since ratio is 3:5
let final velocity v=v1
We know that
v1^2-u^2 = 2*a*s
v1^2=2*a*3x.......Eq(1)
for second body also freely falling ,therefore
u=0
a= g
s=5x
let final velocity v=v2
v2^2-u^2 = 2*a*s
v2^2= 2*a*5x......Eq(2)
Eq (1) / Eq(2)
v1^2/v2^2 = 2*a*3x/ 2*a*5x
(v1/v2)^2 = 3/5
v1/v2 =√3/√5
v1:v2 = √3 : √5