The ratio of the magnetic fields at the centre of a circular coil carrying current to that at a point whose distance is half of the radius of the coil is:
A
2√5:8
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B
5√5:8
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C
5√5:4
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D
2√5:4
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Solution
The correct option is B5√5:8 BCBX=(r2+x2)3/2r3=(r2+r24)3/2r3=(54r2)3/2r3=(54)3/2=5√58