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Question

The ratio of the time taken for 99.9% reaction and half life of the reaction is

A
100
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B
49.95
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C
10
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D
1000
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Solution

The correct option is C 10
For 99.9%completion
R=[R0]99.9100[R0]=0T(99.9%)=2.303klog[R0]0.001[R0]=2.303klog103=2.303×kk ...(i)t12=2.303klog[R0]0.001[R0]=2.303log2k=2.303×0.3010k ...(ii)
Dividing Eq. (i) by Eq. (ii) we get
t(99.9%)t12=30.3010=10


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