Question

The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ${}^{\prime }{a}^{\prime }$ is $3:2$. The value of ${}^{\prime }{a}^{\prime }$ is (g-Acceleration due to gravity on the earth).

• A. $\frac{3g}{2}$
• B. $\frac{g}{3}$
• C. $\frac{2g}{3}$
• D. $g$

Answer 1

The correct option is B $\frac{g}{3}$

Given,

$\frac{W_0}{W}=\frac{3}{2}$

Weight of the man when a lift is at stationary,

$W_0=mg$

The weight of the man when a lift is moving downward with uniform acceleration $a$ is,

$W=m(g-a)$

So, the ratio is $\frac{W_0}{W}=\frac{mg}{m(g-a)}=\frac{3}{2}$

$2g=3g-3a$

$a=\frac{g}{3}$

The correct option is B.