You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Second Law of Motion

The ratio of ...

Question

The ratio of the weight of a man in a stationary lift & when it is moving downward with uniform acceleration 'a' is 3 : 2. The value of 'a' is (g = acceleration due to gravity)

(3/2) g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2/3) g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

g/3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D g/3
$\frac{m g}{m g - m a} = \frac{3}{2}$
or, $2 g = 3 g - 3 a$
or, $g = 3 a$
$a = \frac{g}{3}$
hence,option D is correct.

Suggest Corrections

Similar questions

The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘a’ is 3:2. The value of ‘a’ is (g – Acceleration due to gravity on the earth)

Q. The ratio of the weight of a man in a stationary lift and when it is accelerating downward with uniform acceleration

a

3 : 2

. The value of

a

is (Acceleration due to gravity is

g

)

Q. The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration

^{'} a^{'}

3 : 2

. The value of

^{'} a^{'}

is (

g =

acceleration due to gravity of the earth)

Q. The ratio of the weight of a man in a stationary lift & when it is moving downward with uniform acceleration `a` is

3 : 2

The value of `A` is

Q. The ratio of the weights of a man in a stationary lift and in a lift accelerating downward with a uniform acceleration '

a

' is

3 : 2

. The acceleration of the lift is:

Join BYJU'S Learning Program

The ratio of the weight of a man in a stationary lift & when it is moving downward with uniform acceleration 'a' is 3 : 2. The value of 'a' is (g = acceleration due to gravity)

The correct option is D g/3mgmg−ma=32or, 2g=3g−3aor, g=3a a=g3hence,option D is correct.

The correct option is D g/3
$\frac{m g}{m g - m a} = \frac{3}{2}$
or, $2 g = 3 g - 3 a$
or, $g = 3 a$
$a = \frac{g}{3}$
hence,option D is correct.