The ratio of time taken by two cars P, Q starting from rest moving along a straight road with equal accelerations is $\sqrt{2}$ : 1, then the :

Final velocity of car P > final velocity of car Q.

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Final velocity of car P < final velocity of car Q.

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Ratio of

V_{P}

V_{Q}

is 2 :

\sqrt{2}

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Ratio of distance travelled by car 'P' to car 'Q' is 2 : 1

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Solution

The correct options are
A Final velocity of car P > final velocity of car Q.
D Ratio of distance travelled by car 'P' to car 'Q' is 2 : 1
$t_{P} : t_{Q} = \sqrt{2} : 1; u_{P} = u_{Q} = 0$
$\frac{v_{P}}{v_{Q}} = \frac{t_{P}}{t_{Q}} = \frac{\sqrt{2}}{1} \Rightarrow v_{P} = \sqrt{2} V_{Q}$
$∴$ Final velocity of car P > final velocity of Q
$v_{P} : v_{Q} = 2 : \sqrt{2}$
$\frac{S_{P}}{S_{Q}} = \frac{t_{P}^{2}}{t_{Q}^{2}} = \frac{(\sqrt{2})^{2}}{(1)^{2}} = \frac{2}{1}$

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