Question

The ratio of turns in primary and secondary coils of a transformer is 1:10. The ratio of currents in primary and secondary coils will be

• A. 1:100
• B. 10:1
• C. 1:10
• D. 100:1

Answer 1

Answer: (B)

10:1

Ratio of turns in primary and secondary coils of a transformer is $n_1:n_2=1:10$

$\Rightarrow \frac{n_1}{n_2}=\frac{1}{10}$

Let the currents be $I_1,I_2$

We have $n_1{I}_1=n_2{I}_2$

$\Rightarrow \frac{I_1}{I_2}=\frac{n_2}{n_1}=10$

therefore option $B$ is correct