Question

The ratio of two Bohr's orbit $n_1$ and $n_2$ are in the ratio of $4:9$. If $n_1+n_2=5$ and an electron make transition between these orbits then :

• A. longest wavelength of lyman series will be emitted
• B. longest wavelength of paschen series will be emitted
• C. shortest wavelength of lyman series will be emitted
• D. radiation emitted will have minimum frequency of Balmer series

Answer 1

The correct option is D radiation emitted will have minimum frequency of Balmer series

$\frac{n_1}{n_2}=\frac{4}{9}$

$n_1+n_2=5$
So, $n_1=2,n_2=3$