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Electrolysis and Electrolytes

The ratio of ...

Question

The ratio of volume of $H_{2}$ and $C l_{2}$ evolved at NTP by electrolysis of aqueous solution of $H C l$ is:

1 : 3

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3 : 5

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1 : 1

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1 : 7

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Solution

The correct option is C $1 : 1$
Answer is option $C .$
Electrolysis of $H C l -$
At cathode,
$2 H^{+} + 2 e^{-} ⟶ H_{2 (g)}$
At anode,
$2 C l^{-} ⟶ C l_{2 (g)} + 2 e^{-}$
Theoretically the gas volume ratio is $1 : 1$
as overall reaction is given by,
$2 H_{(a q)}^{+} + 2 C l_{(a q)}^{-} ⟶ H_{2 (g)} + C l_{2 (g)}$

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