The reaction A to B is not feasible but can be possible theough the following series of steps-A - C - D - B- s A - C -50 eV- s C - D -30 eV- s B - D -20 eVThe entropy change for A - B would beA- 60 eVB- -60 eVC- -100 eVD- 100 eV

The correct option is A 60 eVΔ s (A → B) = Δ s (A → C) + Δ s (C → D) + Δ s (D → B) =50 + 30 + ( 20) = 60 eV ...

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Standard XII

Chemistry

Molar and Specific Heat Capacity

The reaction ...

Question

The reaction A to B is not feasible but can be possible theough the following series of steps:
$A \to C \to D \to B$
$Δ s (A \to C) = 50 e V$
$Δ s (C \to D) = 30 e V$
$Δ s (B \to D) = 20 e V$
The entropy change for $A \to B$ would be

100 eV

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60 eV

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- 60 eV

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Solution

The correct option is B 60 eV
$Δ s (A \to B) = Δ s (A \to C) + Δ s (C \to D) + Δ s (D \to B)$
$= 50 + 30 + (- 20) = 60 e V$

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The reaction A to B is not feasible but can be possible theough the following series of steps: A→C→D→B Δs(A→C)=50 eV Δs(C→D)=30 eV Δs(B→D)=20 eV The entropy change for A→B would be

The correct option is B 60 eVΔs(A→B)=Δs(A→C)+Δs(C→D)+Δs(D→B) =50+30+(−20)=60 eV

The reaction A to B is not feasible but can be possible theough the following series of steps:
$A \to C \to D \to B$
$Δ s (A \to C) = 50 e V$
$Δ s (C \to D) = 30 e V$
$Δ s (B \to D) = 20 e V$
The entropy change for $A \to B$ would be

The correct option is B 60 eV
$Δ s (A \to B) = Δ s (A \to C) + Δ s (C \to D) + Δ s (D \to B)$
$= 50 + 30 + (- 20) = 60 e V$