wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

The reaction FeFe2++2e(+0.44 volt) would occur spontaneously with which of the following?
I. PbPb2++2e(+0.13 volt)
II. CuCu2++2e(0.34 volt)
III. 2Ag++2e2Ag0(+0.80 volt)
Select the correct option among the following :

A
I only
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
III only
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
I and III only
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
II and III only
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
I, II and III
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is E I, II and III
Oxidation potential order :
Fe>Pb>Cu>Ag

As the oxidation potential of Fe is more than Pb,Cu,Ag, it can react spontaneously with all three of the substances.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electrochemical Cell
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon