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Reduction of Carboxylic Acids

The reaction ...

Question

The reaction of $R C O N H_{2}$ with a mixture of $B r_{2}$ and $K O H$ gives $R - N H_{2}$ as the main product. The intermediates involved in this reaction are

R C O N H B r

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R N H B r

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R - N = C = O

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R C O N B r_{2}

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Solution

The correct options are
A $R C O N H B r$
C $R - N = C = O$

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Similar questions

R C O N H_{2}

B r_{2}

K O H

R - N H_{2}

R - C O O H

N_{3} H

R {N H}_{2}

R C O N H_{2} + K O H + B r_{2} ⟶

Intermediates formed during the reaction RCONH₂ with Br₂ and KOH are

R - O | | C - N H_{2}

B r_{2}

K O H

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