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Question

The reaction of the formation of phosgene gas from CO and Cl2 is as follows:
CO(g)+Cl2(g)COCl2(g)
In an experiment, starting with equimolecular CO and Cl2 in a 250mL flask, the equilibrium mixture on analysis is found to contain 0.5mole CO, 0.05 mole Cl2 and 0.15 mole COCl2. Calculate the equilibrium constant of the reaction.

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Solution

The equilibrium concentrations are
[CO]= 0.5 mol 250 mL × 1000 mL/L = 2.0 M
[Cl2]= 0.05 mol 250 mL × 1000 mL/L = 0.20 M
[COCl2]= 0.15 mol 250 mL × 1000 mL/L = 0.60 M
The equilibrium constant Kc=[COCl2][CO][Cl2]
Kc=0.60mol/L2.0mol/L×0.20mol/L
Kc=1.5L/mol

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