Question

The reaction $v_{1}A+v_{2}B\to$ products is first order with respect to $A$ and zero- order with respect to $B$.If the reaction is started with $[A{]}_0$ and $[B{]}_0$, the integrated rate expression of this reaction would be:

• A. $ln\frac{[A{]}_0}{[A{]}_0-x}=k_{1}t$
• B. $ln\frac{[A{]}_0}{[A{]}_0-v_{1}x}=k_{1}t$
• C. $ln\frac{[A{]}_0}{[A{]}_0-v_{1}x}=v_1{k}_{1}t$
• D. $ln\frac{[A{]}_0}{[A{]}_0-v_{1}x}=-v_1{k}_{1}t$

Answer 1

The correct option is C $ln\frac{[A{]}_0}{[A{]}_0-v_{1}x}=v_1{k}_{1}t$

Its 1st Order wrt A and Zero Order wrt B.

So, the integrated rate equation of this reaction is,

$ln\frac{\left[A_0\right]}{\left[A_0\right]-v_{1}x}$ = $v_1{k}_{1}t$