Question

The reading of Centigrade thermometer coincides with that of Fahrenheit thermometer in a liquid. The temperature of the liquid is

• A. ${300}^{\circ }C$
• B. ${100}^{\circ }C$
• C. $-{40}^{\circ }C$
• D. $0^{\circ }C$

Answer 1

The correct option is C $-{40}^{\circ }C$

We know that:$\frac{T_c-0}{100-0}=\frac{T_F-32}{212-32}$

Given:$T_C=T_F$

Let $T_C=T_F=x$

$\frac{T_C}{100}=\frac{T_F-32}{180}$

$\frac{x}{5}=\frac{x-32}{9}$

$9x=5x-160$

$x=-{40}^{\circ }$
Final answer (a)