Question

The temperature at which the reading of Fahrenheit thermometer will be double that of a Centigrade thermometer is:

• A. ${160}^{o}C$
• B. ${180}^{o}C$
• C. ${32}^{o}C$
• D. ${100}^{o}C$

Answer 1

The correct option is A ${160}^{o}C$

Given, $F=2C$

$\frac{C}{100}=\frac{F-32}{180}$

$\frac{C}{100}=\frac{2C-32}{180}$
$C\times 9=5(2C-32)$

$9C=10C-10$
$C={160}^{o}C$.