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F=ma

The reading o...

Question

The reading of spring balance when a block is suspended from it in air is 60 newton. This reading is changed to 40 newton when the block is submerged in water. The specific gravity of the block must be therefore

A

3

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B

2

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C

6

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D

3/2

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Solution

The correct option is A 3
Specific gravity of block = $\frac{w e i g h t o f b l o c k i n a i r}{l o s s o f w e i g h t i n w a t e r}$
= $\frac{60}{60 - 40} = 3$

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