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Standard XII

Physics

Fahrenheit Scale

The readings ...

Question

The readings of a thermometer at $0^{\circ} C$ and $100^{\circ} C$ are $50 c m$ and $75 c m$ of mercury column respectively. Find the temperature at which its reading is $80 c m$ of mercury column?

120^{\circ} C

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20^{\circ} C

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100^{\circ} C

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80^{\circ} C

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Solution

The correct option is A $120^{\circ} C$ .
Using formula,
$\frac{(T - T_{L})}{(T_{H} - T_{L})} = \frac{(T - 0)}{(T_{H} - T_{L})} = \frac{(80 - 50)}{(75 - 50)} \Rightarrow T = 120^{o} C$

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The readings of a thermometer at 0∘C and 100∘C are 50cm and 75cm of mercury column respectively. Find the temperature at which its reading is 80cm of mercury column?

The correct option is A 120∘C.Using formula,(T−TL)(TH−TL)=(T−0)(TH−TL)=(80−50)(75−50)⇒T=120oC

The readings of a thermometer at $0^{\circ} C$ and $100^{\circ} C$ are $50 c m$ and $75 c m$ of mercury column respectively. Find the temperature at which its reading is $80 c m$ of mercury column?

The correct option is A $120^{\circ} C$ .
Using formula,
$\frac{(T - T_{L})}{(T_{H} - T_{L})} = \frac{(T - 0)}{(T_{H} - T_{L})} = \frac{(80 - 50)}{(75 - 50)} \Rightarrow T = 120^{o} C$