Question

The reagent(s) for the following conversion
is/are :

• A. Alcoholic $KOH$
• B. Alcoholic $KOH$ followed by $NaN{H}_2$
• C. Aqueous $KOH$ followed by $NaN{H}_2$
• D. $Zn/C{H}_{3}OH$

Answer 1

The correct option is B Alcoholic $KOH$ followed by $NaN{H}_2$

Vicinal dihalides on treatment with alcoholic KOH undergo dehydrohalogenation. One molecule of HX is eliminated to form alkenyl halide which on treatment with sodamide gives alkyne.


Hence, the correct answer is option (b).