The reagent (s) used for softening the temporary hardness of water is/are:

C a_{3} (P O_{4})_{2}

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C a (O H)_{2}

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N a_{2} C O_{3}

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N a O C l

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Solution

The correct options are
A $N a_{2} C O_{3}$
B $C a (O H)_{2}$
C $N a O C l$
Temporary hardness is due to the presence of bicarbonates of $C a$ and $M g$ . Temporary hardness can be removed by clarkes process which involves the addition of slaked lime.
$C a (H C O_{3})_{2} + C a (O H)_{2} \to 2 C a C O_{3} ↓ + 2 H_{2} O$ [Clarke 's method]
$N a O C l + H_{2} O ⇌ H O C l + N a O H$
$O H^{-} + H C O_{3}^{-} \to C O_{3}^{2 -} + H_{2} O$

Washing soda removes both the temporary and permanent hardness
$C a (H C O_{3})_{2} + N a_{2} C O_{3} \to C a C O_{3} ↓ + 2 N a H C O_{3}$

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