The reagent used for converting ethanoic acid to ethanol is

L i A l H_{4}

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K M n O_{4}

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P C l_{3}

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K_{2} C r_{2} O_{7} / H^{+}

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Solution

The correct option is A $L i A l H_{4}$
The $L i A l H_{4}$ is strong reducing agent, it reduces the acid into alcohol.
$C H_{3} C O O H L i A l H_{4} - --- \to C H_{3} C H_{2} O H$

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Suggest a reagent for conversion of ethanol to ethanoic acid.

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