The real number k for which the equation, 2x3+3x+k=0 has two distinct real roots in [0, 1]
A
lies between 1 and 2
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B
lies between 2 and 3
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C
lies between – 1 and 0
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D
does not exist
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Solution
The correct option is Ddoes not exist Let f(x)=2x3+3x+k On dofferentiating w.r.t. x, we get F′(x)=6x2+3>0,∀x∈R ⇒ f(x) is strictly increasing function. ⇒ f(x) = 0 has only one real root, so two roots are not possible.