The reducing agent for the forward reaction in the given reaction is :
$M n^{2 +} + B i O_{3}^{-} \to M n O_{4}^{-} + B i^{3 +}$

B i^{3 +}

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B i O_{3}^{-}

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M n O_{4}^{-}

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M n^{2 +}

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Solution

The correct option is D $M n^{2 +}$
A reducing agent (also called a reductant or reducer) is an element (such as calcium) or compound that loses (or "donates") an electron to another chemical species in a redox chemical reaction. Since the reducing agent is losing electrons, it is said to have been oxidized.
In reaction ${M n}^{2 +} + B i O_{3}^{-} ⟶ M n O_{4}^{-} + {B i}^{3 +}$
${M n}^{2 +}$ is reducing agent as it is oxidized and reduces ${B i}^{3 +}$ .

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{B i}^{3 +} (a q) ⟶ B i O_{3}^{-} (a q)

{B i}^{3 +}

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In the reaction
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