The reducing agent in the following reaction is-Pbs - Cu2-aq - Pb2- aq - Cus

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Oxidation and Reduction

The reducing ...

Question

The reducing agent in the following reaction is:
Pb(s) + Cu²⁺(aq) → Pb²⁺ (aq) + Cu(s)

Pb²⁺ (aq)

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Cu²⁺ (aq)

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Pb (s)

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Cu (s)

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Solution

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Similar questions

Z n (s) + C u^{2 +} (a q) ⟶ Z n^{2 +} (a q) + C u (s)

C u^{2 +} (a q) + Z n (s) \to Z n^{2 +} (a q) + C u (s)

C u_{(s)} \to C u_{(a q)}^{2 +} + 2 e^{-}; E^{o} = - 0.325 V

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}; E^{o} = 0.50 V

E^{o}

2 C u_{(a q)}^{+} \to C u_{(a q)}^{2 +} + C u_{(s)}

E_{C e l l}^{o}

Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)

E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

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