Types of Solutions Based on the Concentration of the Solution
The reduction...
Question
The reduction potential for Cu2+/Cu is +0.34 V. Calculate the reduction potential (in V) at pH=13 for the above couple (assume saturated solution ofCu(OH)2). (Given:Ksp(Cu(OH)2)=10−22)
A
−0.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
−0.25
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
−0.84
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
−0.05
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B−0.25 Given that pH=13 ∴[H+]=10−13 M[OH−]=10−1 M Ksp=[Cu2+][OH−]2=10−22⇒[Cu2+]=10−20
For the half cell reaction, Cu2++2e−⇋Cu, the emf is E=E∘−0.0592log1[Cu2+]=0.34−0.0592log110−20=0.34−0.059×10=0.34−0.59=−0.25V