The reduction potential at pH - 14 for the Cu2-Cu couples is- -Given- EoCu2-Cu-0-34 V- KspCuOH2-1 - 10-19-

The standard reduction potential for $C u^{2 +} | C u$ is $+ 0.34 V$ . Calculate the reduction potential at pH $= 14$ for the above couple if $K_{s p}$ of $C u (O H)_{2}$ is $1.0 \times 10^{- 19}$ .

Q. The standard reduction potential for

C u^{2 +} 1 C u

is +0.34 V. The reduction potential at pH = 14 for the above couple is:

K_{s p}

C u (O H)_{2} i s 1.0 \times 10^{- 19}

Q. The standard reduction potential for

C u^{2 +} / C u

+ 0.34

V. What will be the reduction potential at pH

= 14

? [Given:

K_{s p}

C u (O H)_{2}

1.0 \times 10^{- 19}]

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The reduction potential at pH = 14 for the Cu2+/Cu couples is: [Given, EoCu2+/Cu=0.34V; KspCu(OH)2=1×10−19]

The correct option is D −0.22 VGiven, pH=14,∴pOH=0and [OH−]=1 M[Cu2+][OH−]2=Ksp=1×10−19[Cu2+]=1×10−19MFor the half reaction, Cu2++2e−⟶CuEoCu2+/Cu=EoCu2+/Cu−0.0512log1[Cu2+] =0.34−0.05912log1019 =−0.22 V

The reduction potential at pH = 14 for the $C u^{2 +} / C u$ couples is:

[Given, $E_{C u^{2 +} / C u}^{o} = 0.34 V; K_{s p} C u (O H)_{2} = 1 \times 10^{- 19}]$