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Types of Solutions Based on the Concentration of the Solution

The reduction...

Question

The reduction potential for $C u^{2 +} / C u$ is $+ 0.34 V$ . Calculate the reduction potential $(in V)$ at $p H = 13$ for the above couple $(assume saturated solution of C u (O H)_{2})$ .
$(Given: K_{s p} (C u (O H)_{2}) = 10^{- 22}$ $)$

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- 0.25

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Solution

The correct option is B $- 0.25$
Given that $p H = 13$
$∴ [H^{+}] = 10^{- 13} M [O H^{-}] = 10^{- 1} M$
$K_{s p} = [C u^{2 +}] [O H^{-}]^{2} = 10^{- 22} \Rightarrow [C u^{2 +}] = 10^{- 20}$

For the half cell reaction, $C u^{2 +} + 2 e^{-} ⇋ C u$ , the emf is
$E$ $= E^{\circ} - \frac{0.059}{2} log \frac{1}{[C u^{2 +}]} = 0.34 - \frac{0.059}{2} log \frac{1}{10^{- 20}} = 0.34 - 0.059 \times 10 = 0.34 - 0.59 = - 0.25 V$

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Similar questions

The standard reduction potential for $C u^{2 +} | C u$ is $+ 0.34 V$ . Calculate the reduction potential at pH $= 14$ for the above couple if $K_{s p}$ of $C u (O H)_{2}$ is $1.0 \times 10^{- 19}$ .

Q. The reduction potential at pH = 14 for the

C u^{2 +} / C u

couples is:

[Given,

E_{C u^{2 +} / C u}^{o} = 0.34 V; K_{s p} C u (O H)_{2} = 1 \times 10^{- 19}]

Q. The standard reduction potential of

C u^{2 +} / C u

couple is

0.34

V at

25^{0}

C. Calculate the reduction potential at

p H = 14

for this couple.
Given

K_{s p}

C u (O H)_{2} = 1.0 \times 10^{- 18}

)

Q. The standard reduction potential for

C u^{2 +} / C u

+ 0.34 V

. The reducing potential at

p H = 14

for the above couple is

{[C u^{2 +}] a t p H 14 i s 10^{- 19}}

Q. The standard reduction potential for

C u^{2 +} / C u

+ 0.34

V. What will be the reduction potential at pH

= 14

? [Given:

K_{s p}

C u (O H)_{2}

1.0 \times 10^{- 19}]

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The reduction potential for Cu2+/Cu is +0.34 V. Calculate the reduction potential (in V) at pH=13 for the above couple (assume saturated solution of Cu(OH)2). (Given: Ksp(Cu(OH)2)=10−22)

The correct option is B −0.25Given that pH=13 ∴[H+]=10−13 M[OH−]=10−1 M Ksp=[Cu2+][OH−]2=10−22⇒[Cu2+]=10−20 For the half cell reaction, Cu2++2e−⇋Cu, the emf is E =E∘−0.0592log1[Cu2+]=0.34−0.0592log110−20=0.34−0.059×10=0.34−0.59=−0.25V

The reduction potential for $C u^{2 +} / C u$ is $+ 0.34 V$ . Calculate the reduction potential $(in V)$ at $p H = 13$ for the above couple $(assume saturated solution of C u (O H)_{2})$ .
$(Given: K_{s p} (C u (O H)_{2}) = 10^{- 22}$ $)$