You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XI

Physics

Uniform and Non Uniform

The relation3...

Question

The relation $3 t = \sqrt{3 x} + 6$ describes the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero, is

24 m e t r e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 m e t r e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 m e t r e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Z e r o

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $Z e r o$
$3 t + \sqrt{3 x} + 6 \Rightarrow 3 x = (3 t - 6)^{2}$

$\Rightarrow x = 3 t^{2} - 12 t + 12$

$v = \frac{d x}{d t} = 6 t - 12, f o r v = 0, t = 2 s e c$

$x = 3 (2)^{2} - 12 \times 2 + 12 = 0$

Suggest Corrections

Similar questions

Q. The relation 3t=

\sqrt{3 x}

+6 describes the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero, is

The displacement x of a particle moving in one dimension is related to time t by the equation $t = \sqrt{x} + 3$ where x is in metres and t in seconds. The displacement of the particle when its velocity is zero is

Q. The distance

x

of a particle moving in one-direction, under the action of a constant force is related to time by equation

t = \sqrt{x} + 3

where

x

is in metres,

t

is in seconds.
Find the displacement of the particle when its velocity is zero.

Q. The displacement

x

of a particle moving in one dimension under the action of a constant force is related to time

t

by the equation

t - 3 = \sqrt{x}

where

x

is in metres and

t

is in seconds. Find the displacement of the particle when its velocity is zero.

Q. The displacement

x

of a particle moving in one dimension under the action of a constant force is related to the time

t

by the equation

t = \sqrt{x} + 3 \forall t \in [3, \infty)

, where

x

is in metres and

t

is in seconds.
The displacement of the particle when its velocity is zero is

Join BYJU'S Learning Program

The relation3t=√3x+6describes the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero, is

The correct option is D Zero3t+√3x+6 ⇒ 3x=(3t−6)2 ⇒ x=3t2−12t+12 v=dxdt=6t−12, for v=0,t=2 sec x=3(2)2−12×2+12=0

The relation $3 t = \sqrt{3 x} + 6$ describes the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero, is

The correct option is D $Z e r o$
$3 t + \sqrt{3 x} + 6 \Rightarrow 3 x = (3 t - 6)^{2}$

$\Rightarrow x = 3 t^{2} - 12 t + 12$

$v = \frac{d x}{d t} = 6 t - 12, f o r v = 0, t = 2 s e c$

$x = 3 (2)^{2} - 12 \times 2 + 12 = 0$