The relation3t=√3x+6describes the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero, is
3t+√3x+6 ⇒ 3x=(3t−6)2
⇒ x=3t2−12t+12
v=dxdt=6t−12, for v=0,t=2 sec
x=3(2)2−12×2+12=0