The relation between an ac voltage source and time in SI units is V - 120 sin 100 - t cos 100 - tVThe value of peak voltage and frequency will be respectively-

The correct option is A 60 V and 100Hz V #160;= 120 sin(100π t) cos(100π #160;t) V #160;= 60 sin(200 π t) V #160; #160; #160; ...

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Standard XII

Physics

Power in an AC Circuit

The relation ...

Question

The relation between an ac voltage source and time in SI units is $V = 120 s i n (100 π t) c o s (100 π t)$ V
The value of peak voltage and frequency will be respectively:

120 V and 100 Hz

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\frac{120}{\sqrt{2}}

V and 100 Hz

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60 V and 200Hz

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60 V and 100Hz

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Solution

The correct option is A 60 V and 100Hz
$V = 120 s i n (100 π t) c o s (100 π t)$

$V = 60 s i n (200 π t) V$ $(∵ s i n 2 θ = 2 s i n θ c o s θ)$

Compare it with standard equation , $V = V_{0} s i n ω t$

We get, $V_{0}$ = 60 V
and $ω = 200 π o r 2 π ν = 200 π o r ν = 100 H z$

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The relation between an ac voltage source and time in SI units is V=120sin(100πt)cos(100πt)VThe value of peak voltage and frequency will be respectively:

The correct option is A 60 V and 100HzV=120sin(100πt)cos(100πt)V=60sin(200πt)V (∵sin2θ=2sinθcosθ)Compare it with standard equation , V=V0sinωtWe get, V0 = 60 Vand ω=200πor2πν=200πorν=100Hz

The relation between an ac voltage source and time in SI units is $V = 120 s i n (100 π t) c o s (100 π t)$ V
The value of peak voltage and frequency will be respectively:

The correct option is A 60 V and 100Hz
$V = 120 s i n (100 π t) c o s (100 π t)$

$V = 60 s i n (200 π t) V$ $(∵ s i n 2 θ = 2 s i n θ c o s θ)$

Compare it with standard equation , $V = V_{0} s i n ω t$

We get, $V_{0}$ = 60 V
and $ω = 200 π o r 2 π ν = 200 π o r ν = 100 H z$