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the relation between energf activation and rate constant K1 K2 and temperature T1 T2

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Solution

Dear student,
The relation between activation energy, rate constant and temperature is given as follows:

$\ln (\frac{K_{2}}{K_{1}}) = \frac{E_{a}}{R} (\frac{1}{T_{1}} - \frac{1}{T_{2}}) w h e r e E_{a} i s t h e a c t i v a t i o n e n e r g y K_{1} a n d K_{2} a r e t h e r a t e c o n s \tan t s T_{1} a n d T_{2} a r e t e m p e r a t u r e s$

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