CameraIcon

SearchIcon

MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Features of MOT

the relation ...

Question

the relation between energf activation and rate constant K1 K2 and temperature T1 T2

Open in App

Solution

Dear student,
The relation between activation energy, rate constant and temperature is given as follows:

$\ln (\frac{K_{2}}{K_{1}}) = \frac{E_{a}}{R} (\frac{1}{T_{1}} - \frac{1}{T_{2}}) w h e r e E_{a} i s t h e a c t i v a t i o n e n e r g y K_{1} a n d K_{2} a r e t h e r a t e c o n s \tan t s T_{1} a n d T_{2} a r e t e m p e r a t u r e s$

Regards

Suggest Corrections

thumbs-up

0

Similar questions

Q. Activation energy

(E_{a})

and rate constants (

k_{1}

k_{2}

) of a chemical reaction at two different temperature (

T_{1}

T_{2}

) are related by:

Q. Activation energy

(E_{a})

and rate constant

(k_{1}

k_{2})

of a chemical reaction at two different temperatures

(T_{1}

T_{2})

are related by:

k_{1} =

rate constant at temperature

T_{1}

k_{2} =

rate constant at temperature

T_{2}

for a first-order reaction, then which of the following relations is correct?
[

E_{a} =

activation Energy]

Q. A reaction can take place by two paths.

k_{1}

k_{2}

are rate constants for the two paths &

E_{1}

E_{2}

are their respective activation energies.
At temperature

T_{a} : k_{1} > k_{2}, E_{1} < E_{2}

Its temperature is raised to

T_{b}

, the rate constants change to

k_{1}^{'}

k_{2}^{'}

. Which relation is correct between

k_{1}, k_{2}, k_{1}^{'}

k_{2}^{'}

(considering activation energy does not change with temperature)?

Q. The activation energy for forward and backward reactions are

50 k J / m o l

40 k J / m o l

respectively. If

K_{1}

K_{2}

are the equilibrium constants of reaction at temperature

T_{1}

T_{2}

respectively and

T_{2} > T_{1}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Molecular Orbital Theory

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Features of MOT

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon