The relationship between force and position is shown in the figure given (in one dimensional case). The work done by the force in displacing a body from x = 1 cm to x = 5 cm is

20 ergs

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60 ergs

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70 ergs

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700 ergs

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Solution

The correct option is A
20 ergs

Work done = Covered area on force-displacement graph $= 1 \times 10 + 1 \times 20 - 1 \times 20 + 1 \times 10 = 20 e r g s .$

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The relationship between force and position is shown in the figure given (in one dimensional case). The work done by the force in displacing a body from x = 1 cm to x = 5 cm is

The relationship between force and position is shown in the figure given (in one-dimensional case). Calculate the work done by the force in displacing a body from $x = 0 cm$ to $x = 5 cm$ .

Q. The relationship between force and position is shown in the figure (in one dimensional case). Work done by the force in displacing a body from x

=

1 cm to x

=

5cm is :

Q. How much work is done in ergs in pulling a box

2 m

across a tabletop with a force of

20 N

in the horizontal direction?

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The relationship between force and position is shown in the figure given (in one dimensional case). The work done by the force in displacing a body from x = 1 cm to x = 5 cm is

The correct option is A 20 ergs Work done = Covered area on force-displacement graph =1×10+1×20−1×20+1×10=20 ergs.

The correct option is A
20 ergs

Work done = Covered area on force-displacement graph $= 1 \times 10 + 1 \times 20 - 1 \times 20 + 1 \times 10 = 20 e r g s .$