The relative density of the liquid at the bottom of the U-tube is $11$ . Water is filled over it as shown. The difference in the liquid level in the U-tube is:
$P_{1} - P_{2} = 10^{5} P a$

Δ h = 1 c m

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Δ h = 20 c m

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Δ h = 30 c m

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Δ h = 40 c m

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Solution

The correct option is A $Δ h = 1 c m$
As we know Pressure at point (1) is equal to that at point (2)
Therefore ,
$p_{1}$ + $(1000) g (h_{o} + Δ h)$ = $p_{2}$ + $(1000) g h_{o}$ + $(11000) g Δ h$

so $p_{1} - p_{2}$ = $(10000) g Δ h$

hence , $10^{5}$ = $10^{5} Δ h$ , implies $Δ h$ = 1
so option (A) is correct

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