The relative rates of mononitration of $R - C_{6} H_{5},$ where $R = - C H_{3}, - N O_{2}, - O H, - C l$ are

H_{3} C - C_{6} H_{5} > O H - C_{6} H_{5} > O_{2} N - C_{6} H_{5} > C l - C_{6} H_{5}

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O H - C_{6} H_{5} > C l - C_{6} H_{5} > H_{3} C - C_{6} H_{5} > O_{2} N - C_{6} H_{5}

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O H - C_{6} H_{5} > C H_{3} - C_{6} H_{5} > O_{2} N - C_{6} H_{5} > C l - C_{6} H_{5}

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O H - C_{6} H_{5} > H_{3} C - C_{6} H_{5} > C l - C_{6} H_{5} > O_{2} N - C_{6} H_{5}

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Solution

The correct option is D $O H - C_{6} H_{5} > H_{3} C - C_{6} H_{5} > C l - C_{6} H_{5} > O_{2} N - C_{6} H_{5}$
$- C H_{3}, - O H, - C l$ are ortho-para directing groups and shows +M effect. But $- N O_{2}$ is meta directing group and deactivates the ring and makes the ring difficult for electrophilic substitution reaction.
$- O H$ is strong ring activating group followed by $- C H_{3}$ and $- C l$ .
The relative rates of mononitration is $O H - C_{6} H_{5} > H_{3} C - C_{6} H_{5} > C l - C_{6} H_{5} > O_{2} N - C_{6} H_{5}$

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Similar questions

R - C_{6} H_{5},

R = - C H_{3}, - N O_{2}, - O H, - C l

C H_{3} - C O - C H_{3} \to C H_{3} - C H - C H_{3}

O H

C_{6} H_{5} - C H_{2} - C H_{3} \to C_{6} H_{5} - C O O^{-} K^{+}

S_{N} 1

S_{N} 2

$R - B r + C l^{-} D M F - -- \to R - C l + B r^{-}$

Which one of the following has the highest relative rate?

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