MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Terminal Velocity

The relative ...

Question

The relative velocity of two consecutive water layers is 8cm/s and the perpendicular distance between the layers is 0.1cm. The velocity gradient is?

Open in App

Solution

Dear student,
velocity gradient = dV/dl
dV=8cm/s
dl=0.1cm
Velocity gradient =8/0.1
Velocity gradient =80 per sec
Regards

Suggest Corrections

thumbs-up

0

Similar questions

Q. The relative velocity of two consecutive layers is

8 c m / s

. If the perpendicular distance between the layers is

0.1 c m

, then the velocity gradient will be

The relative velocity between two parallel layers of water is 10 cm/s and the perpendicular distance between them is 0.1 cm. The velocity gradient is

Q. If the shearing stress between the horizontal layers of water in a river is

1.5 m N / m^{2}

η_{w a t e r} = 1 \times 10^{- 3} P a - s

, The velocity gradient is:

Q. If the velocity of water near the surface of a

6

m deep river is

6

/

s, assuming uniform velocity gradient along the depth, find the shear stress between the horizontal layers of water (coefficient of viscosity of water

= 10^{- 2}

Q. According to Newton, the viscous force acting between liquid layers of area

A

and velocity gradient

\frac{Δ v}{Δ z}

F = - η a \frac{d v}{d z}

η

is constant called

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Viscosity

PHYSICS

Watch in App

explore_more_icon

Explore more

Terminal Velocity

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon