The remainder obtained when 64- 65- 66 is divided by 67 is

The correct option is A 61 We know that 64= 3(Mod 67),65= 2 Mod(67),66= 1(Mod 67) ∴ 64× 65× 66=( 3)( 2)( 1)(Mod 67)= 6(Mod 67)=61(Mod 67) Theref ...

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Standard IX

Mathematics

Theorem

The remainder...

Question

The remainder obtained when $64 \times 65 \times 66$ is divided by $67$ is

61

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Solution

The correct option is A $61$
We know that $64 = - 3 (M o d 67), 65 = - 2 M o d (67), 66 = - 1 (M o d 67)$ $∴ 64 \times 65 \times 66 = (- 3) (- 2) (- 1) (M o d 67) = - 6 (M o d 67) = 61 (M o d 67)$
Therefore, remainder is $61$ .
Ans: A

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The remainder obtained when 64×65×66 is divided by 67 is

The correct option is A 61We know that64=−3(Mod67),65=−2Mod(67),66=−1(Mod67) ∴64×65×66=(−3)(−2)(−1)(Mod67)=−6(Mod67)=61(Mod67)Therefore, remainder is 61.Ans: A

The remainder obtained when $64 \times 65 \times 66$ is divided by $67$ is

The correct option is A $61$
We know that $64 = - 3 (M o d 67), 65 = - 2 M o d (67), 66 = - 1 (M o d 67)$ $∴ 64 \times 65 \times 66 = (- 3) (- 2) (- 1) (M o d 67) = - 6 (M o d 67) = 61 (M o d 67)$
Therefore, remainder is $61$ .
Ans: A