The remainder obtained when 64- 65- 66 is divided by 67 is

The correct option is A 61 We know that 64= 3(Mod 67),65= 2 Mod(67),66= 1(Mod 67) ∴ 64× 65× 66=( 3)( 2)( 1)(Mod 67)= 6(Mod 67)=61(Mod 67) Theref ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Theorem

The remainder...

Question

The remainder obtained when $64 \times 65 \times 66$ is divided by $67$ is

61

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $61$
We know that $64 = - 3 (M o d 67), 65 = - 2 M o d (67), 66 = - 1 (M o d 67)$ $∴ 64 \times 65 \times 66 = (- 3) (- 2) (- 1) (M o d 67) = - 6 (M o d 67) = 61 (M o d 67)$
Therefore, remainder is $61$ .
Ans: A

Suggest Corrections

Similar questions

Q. Find the sum of remainder obtained when 64, 65 and 66 are divided by 7.

Q. The remainder obtained when

x^{64} + x^{27} + 1

is divided by x + 1 is

The remainder obtained when $(2 + 5^{2} + 6^{3} + 11^{4} + 2^{5} + 5^{6} + 6^{7} + 11^{8} + \dots \dots 2^{97} + 5^{98} + 6^{99} + 11^{100})$ is divided by 5 is

The remainder obtained when (1! + 2! + 3! + …..100!) is divided by 10 is

The remainder obtained when 1!+2!+3! ……+11! Is divided by 12 is …….

Join BYJU'S Learning Program

The remainder obtained when 64×65×66 is divided by 67 is

The correct option is A 61We know that64=−3(Mod67),65=−2Mod(67),66=−1(Mod67) ∴64×65×66=(−3)(−2)(−1)(Mod67)=−6(Mod67)=61(Mod67)Therefore, remainder is 61.Ans: A

The remainder obtained when $64 \times 65 \times 66$ is divided by $67$ is

The correct option is A $61$
We know that $64 = - 3 (M o d 67), 65 = - 2 M o d (67), 66 = - 1 (M o d 67)$ $∴ 64 \times 65 \times 66 = (- 3) (- 2) (- 1) (M o d 67) = - 6 (M o d 67) = 61 (M o d 67)$
Therefore, remainder is $61$ .
Ans: A