Question

The remainder when $3x^3+2x^2-x+4$ is divided by $3+2x$ is $\frac{-1}{8}$.

• A.
• B.

Answer 1

The correct option is A

Let $p\left(x\right)=3x^3+2x^2-x+4$

Then, according to the remainder theorem, the required remainder is $p\left(\frac{-3}{2}\right)$.

$\therefore$ Remainder $=3(\frac{-3}{2}{)}^3+2(\frac{-3}{2}{)}^2-\left(\frac{-3}{2}\right)+4$

$=\frac{-1}{8}$

Thus, the given statement is true.