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Question

The remainder when
x=55..5 (24 times 5)
is divided by 24 is

A
1
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B
3
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C
5
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D
23
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Solution

The correct option is C 5
Note that
x=55..5 (23 times 5)
is an odd natural number. Therefore
x=52ni+1=(25m)5
where m is a natural number. Thus,
x=(24+1)m5=5+a multiple of 24.
Hence, the desired remainder is 5.

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